5/7+9/7x=2/x^2

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Solution for 5/7+9/7x=2/x^2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(9/7)*x+5/7 = 2/(x^2) // - 2/(x^2)

(9/7)*x-(2/(x^2))+5/7 = 0

(9/7)*x-2*x^-2+5/7 = 0

9/7*x^1-2*x^-2+5/7*x^0 = 0

(9/7*x^3+5/7*x^2-2*x^0)/(x^2) = 0 // * x^4

x^2*(9/7*x^3+5/7*x^2-2*x^0) = 0

x^2

(9/7)*x^3+(5/7)*x^2-2 = 0

(9/7)*x^3+(5/7)*x^2-2 = 0 // * 0

{ 1, -1, 2, -2, 7, -7, 14, -14 }

1

x = 1

9*x^3+5*x^2-14 = 0

1

x-1

9*x^2+14*x+14

9*x^3+5*x^2-14

x-1

9*x^2-9*x^3

14*x^2-14

14*x-14*x^2

14*x-14

14-14*x

0

9*x^2+14*x+14 = 0

DELTA = 14^2-(4*9*14)

DELTA = -308

DELTA < 0

x in { 1} 

x = 1

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